13 point question, Surds, geometry and Algebra. Help me please ! :( < 3

Answer:A)  Tan 60° [tex]\sqrt{3}[/tex] = 1.732B)  H = 12 unitC)  Area of triangle = 41.569 unit²Step-by-step explanation:As shown in figure, the triangle with cone angle of 60° and base value 4[tex]\sqrt{3}[/tex] unitA) Now, Tan 60° = [tex]\sqrt{3}[/tex]    Or, Tan 60° = 1.732 B) To  find value of h    since TanФ = [tex]\frac{Perpendicular}{Base}[/tex]    So,     Tan 60° = [tex]\frac{h}{4\sqrt{3} }[/tex]                [tex]\sqrt{3}[/tex] = [tex]\frac{h}{4\sqrt{3} }[/tex]            ∴([tex]\sqrt{3}[/tex]) × ([tex]4\sqrt{3}[/tex] = h            ∴ h = 12 unitC) Area of this triangle = [tex]\frac{1}{2}[/tex] × Perpendicular × Base                                      = [tex]\frac{1}{2}[/tex] × h ×[tex]4\sqrt{3}[/tex]       ∵ Perpendicular  h = 12 unit    So, Area = [tex]\frac{1}{2}[/tex] × 12 × [tex]4\sqrt{3}[/tex]    Hence Area of triangle = 41.569 unit²ANSWER